Calculation
The standard brick size in the United States, as controlled by the American Society for Testing and Materials (ASTM), is 8" x 4" x 4" inches. This size is put in the order of length, breadth, and height. ..
In this conversion, we will use 12 inches as the unit of measurement.
Now, when we are speaking of an area, we consider the length and breadth. So, as the length = 8” and breadth= 4”.
The surface area of a brick is the length x width.
The square inch is a unit of measurement used in the United States. It is equal to 8 inches by 4 inches.
we would need to consider the following: How many bricks are in an inch? How many bricks are in a foot? How many bricks are in a yard? Now, as we are considering 100 bricks, so the total area covered by 1000 such bricks, we would need to consider the following: How many bricks are in an inch? How many bricks are in a foot? How many bricks are in a yard?
This is a calculation.
Since 1 foot = 12 inches, so 1 inch = 1/12 foot.
This is a very simple calculation that can be used to figure out how much space is in a room. 1 square inch = 1/12 X 1/12 = 1/144 square foot.
120 square feet per inch. ..
The average square foot in the United States is 1,144. So, if you want to build a house that will fit within 12,000 square feet of a single square foot of land, you would need to purchase and build an entire house on one acre.
The 1000 bricks can cover 83.33 square feet of area in a single layer.
Do all the bricks across the globe always cover the same area when taken in the same number as above?
Bricks from different countries of the world have different shapes. Even though the same country has different dimensions of bricks in different regions. So, 1000 of these bricks taken from different regions always covers a different area. Whenever the dimensions of the brick change, the area covered by it also changes. So, they never occupy the same area.
Can the area calculated above be calculated in other unit systems?
We have already seen that the area is covered by the 1000 bricks, each of standard US dimensions of 8" x 4" x 4", we shall now see how to convert them into CGS and MKS systems. ..
FPS
In the FPS (Foot-pound-seconds) system, a foot was equal to 30.48 centimeters. However, we now know that 1 centimeter is equal to 1 foot. So in order to make this conversion more easily understandable, we have used the unit of length, centimeters.
This is a calculation that can be used to measure the size of objects. 1 square foot is equal to 929.03 square centimetres.
This is a calculation that shows how much space is needed to fit a certain number of people in a certain area.
So, as we have seen, 1000 bricks of dimensions 8" x 4" x 4" will cover a dimension of 83.33 square foot or 7741.103 square meters. ..
MKS (Metre-kilogram-second):
What are bricks made up of?
In different places on the earth, bricks are made up of different materials and in different processes.
In the tropical and equatorial regions, the bricks are made of mud.
In many places, ash is used to make bricks. Ash is collected from the burning of waste materials and other undesired elements.
Rocks are a common building material in many regions of the world. In the olden days, when the soil was rock and hardy, rocks were used as bricks. One can find many rock castles and forts dotting the European landscape.
In the polar regions, people still use snow to make bricks to make traditional igloos. Though nowadays, the modern technology of brick making is also used there, igloos can still be seen. ..
Conclusion:
So, from the above calculations, it can be seen that 1000 bricks, which have dimensions 8" x 4" x 4" inches, in the order of length x width/breadth x height, will cover an area of 12,000 square inches or 83.33 square feet. ..
Bricks can be substituted with other building materials, such as concrete or steel. ..
Nowadays, various methods are available to substitute bricks. In many regions, buildings are made up of rocks, sandstones, or limestones. Also, in modern days, they are substituted by concrete or mainly by using metal structures in erection processes. ..
